**Calculating the Reactance of a Capacitor**

### Introduction

In electrical engineering, capacitors are widely used in electronic circuits to store energy and filter out unwanted frequencies. One important characteristic of a capacitor is its reactance, which is a measure of how much it resists changes in voltage at a given frequency. In this article, we'll explore how to calculate the reactance of a 10nF capacitor at a frequency of 1MHz.

### What is Reactance?

**Reactance (X)** is a measure of how much a capacitor or inductor resists changes in voltage or current at a given frequency. It is measured in ohms (Ω) and is a complex quantity that depends on the frequency of the signal.

For a capacitor, the reactance is inversely proportional to the frequency and capacitance. The higher the frequency or capacitance, the lower the reactance.

### The Formula for Capacitive Reactance

The formula for calculating the reactance of a capacitor is:

**Xc = 1 / (2 * π * f * C)**

Where:

**Xc**is the capacitive reactance in ohms (Ω)**f**is the frequency in hertz (Hz)**C**is the capacitance in farads (F)

### Calculating the Reactance of a 10nF Capacitor at 1MHz

Now, let's plug in the values to calculate the reactance of a 10nF capacitor at a frequency of 1MHz:

**C**= 10nF = 10 x 10^(-9) F**f**= 1MHz = 1 x 10^6 Hz

Substituting these values into the formula, we get:

**Xc = 1 / (2 * π * 1 x 10^6 Hz * 10 x 10^(-9) F)**
**Xc ≈ 159.15 Ω**

Therefore, the reactance of a 10nF capacitor at a frequency of 1MHz is approximately 159.15 ohms.

### Conclusion

In this article, we've seen how to calculate the reactance of a capacitor using the formula **Xc = 1 / (2 * π * f * C)**. By plugging in the values for a 10nF capacitor at 1MHz, we found that the reactance is approximately 159.15 ohms. This calculation is essential in designing and analyzing electrical circuits, particularly those involving capacitors.