**Solving Simultaneous Linear Equations by Substitution Method**

In this article, we will solve a system of simultaneous linear equations using the substitution method. The given equations are:

**Equation 1:** x + 2y - 4 = 0
**Equation 2:** 2x + 4y - 12 = 0

**Step 1: Rearrange Equation 1**

Rearrange Equation 1 to isolate x:

x + 2y - 4 = 0 x = -2y + 4

**Step 2: Substitute x into Equation 2**

Substitute the expression of x from Equation 1 into Equation 2:

2x + 4y - 12 = 0 2(-2y + 4) + 4y - 12 = 0

**Step 3: Simplify and Solve for y**

Expand and simplify the equation:

-4y + 8 + 4y - 12 = 0 -4y + 4y + 8 - 12 = 0 0y - 4 = 0 y = 4/4 y = 1

**Step 4: Substitute y back into Equation 1**

Substitute the value of y back into Equation 1 to find the value of x:

x = -2y + 4 x = -2(1) + 4 x = -2 + 4 x = 2

**Solution**

The solution to the system of equations is:

x = 2 y = 1

Therefore, the point of intersection of the two lines is (2, 1).